document.write( "Question 1023621: Please help and show all work. Thanks\r
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\n" ); document.write( " Real Zeros of Polynomials\r
\n" ); document.write( "\n" ); document.write( "1. The polynomial of degree 4, P(x) has a root of multiplicity 2 at x=3 and roots of multiplicity 1 at x=0 and x=−2. It goes through the point (5,14). \r
\n" ); document.write( "\n" ); document.write( "Find a formula for P(x). \r
\n" ); document.write( "\n" ); document.write( "P(x)=\r
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\n" ); document.write( "\n" ); document.write( "2. The polynomial of degree 3, P(x), has a root of multiplicity 2 at x=5 and root of multiplicity 1 at x=-1. The y-intercept is y=-12.5. \r
\n" ); document.write( "\n" ); document.write( "Find a formula for P(x). \r
\n" ); document.write( "\n" ); document.write( "P(x)=
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Algebra.Com's Answer #639175 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
1. A polynomial with a root of multiplicity 2 at x=3 has \"%28x-3%29%5E2\" as a factor.
\n" ); document.write( "A polynomial with roots of multiplicity 1 at x=0 and x=−2
\n" ); document.write( "has \"%28x-0%29=x\" and \"%28x-%28-2%29%29=%28x%2B2%29\" as factors.
\n" ); document.write( "The factors listed make
\n" ); document.write( "\"P%28x%29=a%2Ax%2A%28x%2B2%29%2A%28x-3%29%5E2\" , with \"a%3C%3E0\" a polynomial f degree 4.
\n" ); document.write( "If the graph of such polynomial goes through point (5,14), then \"P%285%29=14\" ,and \"a%2A5%2A%285%2B2%29%2A%285-3%29%5E2=14\" , so
\n" ); document.write( "\"a%2A5%2A7%2A2%5E2=14\"-->\"a%2A5%2A7%2A4=14\"-->\"a=14%2F%285%2A7%2A4%29\"-->\"a=0.1\" .
\n" ); document.write( "So, \"highlight%28P%28x%29=0.1%2Ax%2A%28x%2B2%29%2A%28x-3%29%5E2%29\" is a formula for such a polynomial.
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\n" ); document.write( "2. Similarly, the polynomial must be of the form
\n" ); document.write( "\"P%28x%29=a%2A%28x%2B1%29%2A%28x-5%29%5E2\" , with \"a%3C%3E0\" ,
\n" ); document.write( "ana if the y-intercept is \"-12.5\" ,
\n" ); document.write( "\"a\" must be such that \"P%280%29=12.5\" .
\n" ); document.write( "So, \"a%2A%280%2B1%29%2A%280-5%29%5E2=12.5\"-->\"a%2A1%2A25=12.5\"-->\"a%2A25=12.5\"-->\"a=12.5%2F25\"-->\"a=0.5\",
\n" ); document.write( "and \"highlight%28P%28x%29=0.5%2A%28x%2B1%29%2A%28x-5%29%5E2%29\" is a formula for such a polynomial.
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