document.write( "Question 1023528: factor and find all the zeros. one factor has been given f(x)=x^4+5x^3+8x+40; x+5 \n" ); document.write( "
Algebra.Com's Answer #639057 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "-5        |      1       5      8      40\r\n" );
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document.write( "          |             -5      0      -40\r\n" );
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document.write( "                 1      0       8      0\r\n" );
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\n" ); document.write( "First factorization is \"f%28x%29=%28x%2B5%29%28x%5E3%2B8%29\".
\n" ); document.write( "You can play with possible factors or roots for the new cubic factor or can use a formula sum of cubes directly.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28f%28x%29=%28x%2B5%29%28x%2B2%29%28x%5E2-2x%2B4%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "Look at the zeros of that quadratic factor.
\n" ); document.write( "\"x=%282%2B-+sqrt%28%28-2%29%5E2-4%2A1%2A4%29%29%2F2\"
\n" ); document.write( "\"x=%282%2B-+sqrt%28-12%29%29%2F2\"
\n" ); document.write( "\"x=%282%2B-+i%2A2%2Asqrt%283%29%29%2F2\"
\n" ); document.write( "\"highlight%28x=1%2B-+i%2Asqrt%283%29%29\", and other Real zero is -2.
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