document.write( "Question 1023230: Using your knowledge of similarity and the relationships in a right triangle, write a two column proof of the Pythagorean Thereom from the diagram below of right triangle ABC with altitude CD drawn to hypotenuse AB. \n" ); document.write( "

Algebra.Com's Answer #638993 by Edwin McCravy(20064) $\"\"$ $\"About$

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document.write( "1. ΔACD∽ΔCBD∽ΔABC             1.If an altitude is drawn to the \r\n" );
document.write( "                               hypotenuse of a given right \r\n" );
document.write( "                               triangle, the two right \r\n" );
document.write( "                               triangles formed are similar \r\n" );
document.write( "                               to each other and to the given \r\n" );
document.write( "                               triangle.\r\n" );
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document.write( "2.                    2. Corresponding parts of\r\n" );
document.write( "                               similar triangles\r\n" );
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document.write( "3.  AC² = AD×AB                3. Product of means equal\r\n" );
document.write( "                               product of extremes (in 2)\r\n" );
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document.write( "4.                    4. Corresponding parts of\r\n" );
document.write( "                               similar triangles\r\n" );
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document.write( "5.  BC² = BD×AB                5. Product of means equal\r\n" );
document.write( "                               product of extremes (in 4)\r\n" );
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document.write( "6.  AC²+BC² = AD×AB+BD×AB      6. Equals added to equals\r\n" );
document.write( "                               gives equals\r\n" );
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document.write( "7.  AC²+BC² = AB×(AD+BD)       7. Distributive property\r\n" );
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document.write( "8.  AD+BD = AB                 8. A whole equals the sum \r\n" );
document.write( "                               of its parts.\r\n" );
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document.write( "9.  AC²+BC² = AB×AB            9. Substitution\r\n" );
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document.write( "10. AC²+BC² = AB²             10. AB×AB = AB²\r\n" );
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document.write( "Edwin

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