document.write( "Question 1023373: A can of soda at 80° F. is placed in a refrigerator that maintains a constant temperature of 36° F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by\r
\n" ); document.write( "\n" ); document.write( "T(t) = 36 + 44 e – 0.058 t
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\n" ); document.write( "ind the temperature of the soda 12 minutes after it is placed in the refrigerator. (Round to the
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Algebra.Com's Answer #638950 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"T%28t%29+=+36+%2B+44e%5E%28-0.058t%29\"\r
\n" ); document.write( "\n" ); document.write( "At t=12, \"T%2812%29+=+36+%2B+44e%5E%28-0.058%2A12%29+=+57.94\" degrees Fahrenheit.
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