document.write( "Question 1023322: Separate the number 38 into three parts so that the second number is 2 less than the first number which is one half the third number \n" ); document.write( "

Algebra.Com's Answer #638942 by ikleyn(52796) $\"\"$ $\"About$

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\n" ); document.write( "Separate the number 38 into three parts so that the second number is 2 less than the first number which is one half the third number
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\n" ); document.write( "\n" ); document.write( "Let x = first number.
\n" ); document.write( "Then the second number is (x-2) and the third number is 2x.\r
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\n" ); document.write( "\n" ); document.write( "The condition says that\r
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\n" ); document.write( "\n" ); document.write( "x + (x-2) + 2x = 38,\r
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\n" ); document.write( "\n" ); document.write( "4x - 2 = 38,\r
\n" ); document.write( "\n" ); document.write( "4x = 38 + 2,\r
\n" ); document.write( "\n" ); document.write( "4x = 40,\r
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\n" ); document.write( "\n" ); document.write( "x = $\"40%2F4\"$ = 10.\r
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\n" ); document.write( "\n" ); document.write( "The three numbers are 10, 8, and 20.\r
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