document.write( "Question 1023434: Please help me prove this identity by working on only ONE side of the equation
\n" ); document.write( "(sin^3(A) + cos^3(A)) / (sin^2(A) + 2sin(A)cos(A) + cos^2(A)) = (1 / (sin(A) + cos(A))) - (cos(A) / (1 + cot(A)))\r
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Algebra.Com's Answer #638931 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We work with the left side:\r\n" );
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document.write( "Let s = sin(A) \r\n" );
document.write( "Let c = cos(A)\r\n" );
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document.write( "Factor numerator as the sum of two cubes\r\n" );
document.write( "and the trinomial in the denominator\r\n" );
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document.write( "\"%28%28s%2Bc%29%28s%5E2-sc%2Bc%5E2%29%29%2F%28%28s%2Bc%29%28s%2Bc%29%29\"\r\n" );
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document.write( "Cancel the (s+c)'s\r\n" );
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document.write( "\"%28%28cross%28s%2Bc%29%29%28s%5E2-sc%2Bc%5E2%29%29%2F%28%28cross%28s%2Bc%29%29%28s%2Bc%29%29\"\r\n" );
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document.write( "\"%28s%5E2-sc%2Bc%5E2%29%2F%28s%2Bc%29\"\r\n" );
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document.write( "Replace s and c by what we let them be above:\r\n" );
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document.write( "By a well known identity, looking at the first\r\n" );
document.write( "and third terms, the numerator becomes\r\n" );
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document.write( "We break that into two fractions:\r\n" );
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document.write( "In the second fraction, divide every term,\r\n" );
document.write( "top and bottom by sin(A)\r\n" );
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document.write( "Cancel the sin(A)'s in the top, and the sin(A)'s in the bottom\r\n" );
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document.write( "By using a well-known identity for cot(A):\r\n" );
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document.write( "Edwin
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