document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023342>Question 1023342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one bag contains 43 coins, coins are $2 and $5. find the number of coins of each denomination if there is $167 in total<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638872 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers of $2 and $5 coins, x and y.  Then we write<BR>\n" );
document.write( "x + y = 43 and the value equation is<BR>\n" );
document.write( "2x + 5y = 167<BR>\n" );
document.write( "Multiply the top one by two and subtract...we get<BR>\n" );
document.write( "2x + 5y = 167<BR>\n" );
document.write( "-(2x + 2y = 86)<BR>\n" );
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document.write( "3y = 81<BR>\n" );
document.write( "y = 27 $5 coins and thus there are<BR>\n" );
document.write( "x = 16 $2 coins </SPAN>\n" );
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