document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023355>Question 1023355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a distribution for which the mean is 25 and the standard deviation is 5, what percentage of all scores occur at 30 or below? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638871 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Scores 30 and above occur at greater than or equal to one standard deviation above the mean.<BR>\n" );
document.write( "We know 68.2% of a sample fits within one standard deviation.  Thus the part more than 1 s.d. is (1/2)(100% - 68.2%) = (1/2)(31.8%) = 15.9%<BR>\n" );
document.write( "Thus all the scores at 30 or below would be<BR>\n" );
document.write( "100% - 15.9% = 84.1% </SPAN>\n" );
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