document.write( "Question 1023364: A plane flies roundtrip between Great Hall and Bradford. The trip is 450 miles each way. The trip with the wind​ (the wind going in the same​ direction) takes 4.5 ​hours, while the trip against the wind takes 5 hours. What is the speed of the plane in still​ air? What is the speed of the​ wind? \n" ); document.write( "
Algebra.Com's Answer #638855 by fractalier(6550)\"\" \"About 
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Call the speed of the plane in still air, r.
\n" ); document.write( "Call the speed of the wind, w.
\n" ); document.write( "Thus the rate with the wind is r + w, and
\n" ); document.write( "the rate against the wind is r - w.
\n" ); document.write( "Now, since rate times time equals distance, we can write
\n" ); document.write( "4.5(r+w) = 450 and
\n" ); document.write( "5(r-w) = 450
\n" ); document.write( "which we can simplify, dividing the time, to
\n" ); document.write( "r + w = 100
\n" ); document.write( "r - w = 90
\n" ); document.write( "Now add these and get
\n" ); document.write( "2r = 190
\n" ); document.write( "r = 95 mph
\n" ); document.write( "so that the wind is
\n" ); document.write( "w = 5 mph
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