document.write( "Question 1023364: A plane flies roundtrip between Great Hall and Bradford. The trip is 450 miles each way. The trip with the wind (the wind going in the same direction) takes 4.5 hours, while the trip against the wind takes 5 hours. What is the speed of the plane in still air? What is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #638855 by fractalier(6550) You can put this solution on YOUR website! Call the speed of the plane in still air, r. \n" ); document.write( "Call the speed of the wind, w. \n" ); document.write( "Thus the rate with the wind is r + w, and \n" ); document.write( "the rate against the wind is r - w. \n" ); document.write( "Now, since rate times time equals distance, we can write \n" ); document.write( "4.5(r+w) = 450 and \n" ); document.write( "5(r-w) = 450 \n" ); document.write( "which we can simplify, dividing the time, to \n" ); document.write( "r + w = 100 \n" ); document.write( "r - w = 90 \n" ); document.write( "Now add these and get \n" ); document.write( "2r = 190 \n" ); document.write( "r = 95 mph \n" ); document.write( "so that the wind is \n" ); document.write( "w = 5 mph \n" ); document.write( " |