document.write( "Question 1023346: Consider the curve with equation y^2 = x^3 + 3x^2.\r
\n" ); document.write( "\n" ); document.write( "a. Find an equation of the tangent line to this curve at the point( 1,2).
\n" ); document.write( "b. At what points does this curve have horizontal tangents? Justify your answer algebraically using a derivative.
\n" ); document.write( "c. Can you find the name of this curve?
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Algebra.Com's Answer #638850 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Differentiate implicitly,
\n" ); document.write( "\"2ydy=3x%5E2dx%2B6xdx\"
\n" ); document.write( "\"%282y%29dy=%283x%5E2%2B6x%29dx\"
\n" ); document.write( "\"dy%2Fdx=%283x%5E2%2B6x%29%2F%282y%29\"
\n" ); document.write( "So at (1,2),
\n" ); document.write( "\"dy%2Fdx=%283%281%29%5E2%2B6%281%29%29%2F%282%282%29%29\"
\n" ); document.write( "\"dy%2Fdx=%283%2B6%29%2F4\"
\n" ); document.write( "\"dy%2Fdx=9%2F4\"
\n" ); document.write( "Using the point-slope form,
\n" ); document.write( "\"y-2=%289%2F4%29%28x-1%29\"
\n" ); document.write( "\"y-2=%289%2F4%29x-9%2F4\"
\n" ); document.write( "\"y=%289%2F4%29x-9%2F4%2B8%2F4\"
\n" ); document.write( "\"y=%289%2F4%29x-1%2F4\"
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\n" ); document.write( "b) When the derivative equals zero, the numerator must equal zero so,
\n" ); document.write( "\"3x%5E2%2B6x=0\"
\n" ); document.write( "\"3x%28x%2B2%29=0\"
\n" ); document.write( "Two solutions,
\n" ); document.write( "\"x=0\"
\n" ); document.write( "However, when \"x=0\", \"y=0\", so then the derivative is undefined since there is a division by zero so this \"x\" value is not allowed.
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\n" ); document.write( "\"x%2B2=0\"
\n" ); document.write( "\"x=-2\"
\n" ); document.write( "So here there are two tangents,
\n" ); document.write( "\"y%5E2=%28-2%29%5E3%2B3%28-2%29%5E2\"
\n" ); document.write( "\"y%5E2=-8%2B12\"
\n" ); document.write( "\"y%5E2=4\"
\n" ); document.write( "\"y=2\" and \"y=-2\"
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\n" ); document.write( ".\r
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\n" ); document.write( "c) Fred or it might be George.
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