document.write( "Question 1023321: Find the rational numbers a and b given that
\n" ); document.write( "a-2b + sqr(a+b) = sqr(6)/2\r
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Algebra.Com's Answer #638825 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"I%5B1%5D=sqrt%286%29%2F2\" is an irrational number,
\n" ); document.write( "so \"a-2b%2Bsqrt%28a%2Bb%29\" must be irrational too.
\n" ); document.write( "Since \"a\" and \"b\" are rational,
\n" ); document.write( "\"R=a-2b\" must be rational.
\n" ); document.write( "Since \"a-2b%2Bsqrt%28a%2Bb%29\" is irrational, and
\n" ); document.write( "\"R=a-2b\" is rational,
\n" ); document.write( "\"I%5B2%5D=sqrt%28a%2Bb%29\" must be irrational.
\n" ); document.write( "What we have in \"a-2b%2Bsqrt%28a%2Bb%29=sqrt%286%29%2F2\" is
\n" ); document.write( "\"R%2BI%5B2%5D=I%5B1%5D\" .
\n" ); document.write( "The only way that can be possible is
\n" ); document.write( "\"system%28R=0%2CI%5B2%5D=I%5B1%5D%29\" , which means
\n" ); document.write( "\"system%28a-2b=0%2Csqrt%28a%2Bb%29=sqrt%286%29%2F2%29\"-->\"system%28a=2b%2Ca%2Bb=6%2F4%29\"-->\"system%28a=2b%2C2b%2Bb=3%2F2%29\"-->
\n" ); document.write( "\"system%28a=2b%2C3b=3%2F2%29\"-->\"system%28a=2b%2Cb=1%2F2%29\"-->\"highlight%28system%28a=1%2Cb=1%2F2%29%29\"
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