document.write( "Question 1023290: Find a polynomial function of least degree having only one real coefficients, a leading coefficient of 1, and roots 1-square root 3 , 1+square root 3, and 6-i . \n" ); document.write( "
Algebra.Com's Answer #638816 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The roots we know of are the real roots
\n" ); document.write( "\"x%5B1%5D=1-sqrt%283%29\" , and \"x%5B2%5D=1%2Bsqrt%283%29\" ,
\n" ); document.write( "and the complex root \"x%5B3%5D=6-i\" .
\n" ); document.write( "For the polynomial to have only real coefficients,
\n" ); document.write( "it must also have the conjugate complex root \"x%5B4%5D=6%2Bi\" .
\n" ); document.write( "So, the polynomial of least degree, with a leading coefficient of \"red%281%29\" is
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\n" ); document.write( "\"P%28x%29=%28x-1%2Bsqrt%283%29%29%2A%28x-1-sqrt%283%29%29%2A%28x-6%2Bi%29%2A%28x-6-i%29\"
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\n" ); document.write( "\"P%28x%29=%28%28x-1%29%5E2-%28sqrt%283%29%29%5E2%29%2A%28%28x-6%29%5E2-i%5E2%29\"
\n" ); document.write( "\"P%28x%29=%28%28x%5E2-2x%2B1%29-3%29%2A%28%28x%5E2-12x%2B36%29-%28-1%29%29\"
\n" ); document.write( "\"P%28x%29=%28x%5E2-2x-2%29%2A%28%28x%5E2-12x%2B36%29%2B1%29\"
\n" ); document.write( "\"P%28x%29=%28x%5E2-2x-2%29%2A%28x%5E2-12x%2B37%29\"
\n" ); document.write( "From here on, it is just busywork.
\n" ); document.write( "That is the part where I get bored and distracted, and make mistakes, so check my math from this point on.
\n" ); document.write( "\"P%28x%29=x%5E2%2A%28x%5E2-12x%2B37%29-2x%2A%28x%5E2-12x%2B37%29-2%2A%28x%5E2-12x%2B37%29\"
\n" ); document.write( "\"P%28x%29=%28x%5E4-12x%5E3%2B37x%5E2%29-%282x%5E3-24x%5E2%2B74x%29-%282x%5E2-24x%2B74%29\"
\n" ); document.write( "\"P%28x%29=x%5E4-12x%5E3%2B37x%5E2-2x%5E3%2B24x%5E2-74x-2x%5E2%2B24x-74\"
\n" ); document.write( "\"P%28x%29=x%5E4-14x%5E3%2B59x%5E2-50x-74\"\r
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