document.write( "Question 87999: The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34in., find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #63881 by uma(370) ![]() You can put this solution on YOUR website! Let the width be x cm\r \n" ); document.write( "\n" ); document.write( "Then length measures = 2x+2\r \n" ); document.write( "\n" ); document.write( "The perimeter given to be 34\r \n" ); document.write( "\n" ); document.write( "==> 2[x+2x+2) = 34\r \n" ); document.write( "\n" ); document.write( "==> 2[3x+2] = 34\r \n" ); document.write( "\n" ); document.write( "==> 6x + 4 = 34\r \n" ); document.write( "\n" ); document.write( "==> 6x = 34 - 4\r \n" ); document.write( "\n" ); document.write( "==> 6x = 30\r \n" ); document.write( "\n" ); document.write( "==> x = 5\r \n" ); document.write( "\n" ); document.write( "Thus the width = 5 in\r \n" ); document.write( "\n" ); document.write( "and length = 2(5)+2\r \n" ); document.write( "\n" ); document.write( " = 10+2\r \n" ); document.write( "\n" ); document.write( " = 12 in\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good Luck!!!! \n" ); document.write( " |