document.write( "Question 1023270: Use elimination to solve the problem.\r
\n" ); document.write( "\n" ); document.write( "The sum of the digits of a two-digit number is 11. If the digits are reversed, the new number is 45 more than the original number. Find the number.
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Algebra.Com's Answer #638782 by ankor@dixie-net.com(22740)\"\" \"About 
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a = original 10's digit
\n" ); document.write( "b = original units
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\n" ); document.write( "The sum of the digits of a two-digit number is 11.
\n" ); document.write( "a + b = 11
\n" ); document.write( " If the digits are reversed, the new number is 45 more than the original number.
\n" ); document.write( "10a + b = 10b + a + 45
\n" ); document.write( "10a - a + b - 10b = 45
\n" ); document.write( "9a - 9b = 45
\n" ); document.write( "simplify divide by 9
\n" ); document.write( "a - b = 5
\n" ); document.write( ":
\n" ); document.write( "use elimination on these two equation
\n" ); document.write( "a + b = 11
\n" ); document.write( "a - b = 5
\n" ); document.write( "--------------adding eliminates b, find a
\n" ); document.write( "2a + 0 = 16
\n" ); document.write( "a = 16/2
\n" ); document.write( "a = 8
\n" ); document.write( "find b
\n" ); document.write( "a + b = 11
\n" ); document.write( "8 + b = 11
\n" ); document.write( "b = 11 - 8
\n" ); document.write( "b = 3
\n" ); document.write( " Find the number. 83
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\n" ); document.write( "Check this, subtract;
\n" ); document.write( "83
\n" ); document.write( "38
\n" ); document.write( "---
\n" ); document.write( "45
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