document.write( "Question 1023155: In a certain positive fraction the denominator is greater than the numerator by 3 if 1 is subtracted from both the numerator and denominator the fraction is decreased by 1/14.find the fraction \n" ); document.write( "
Algebra.Com's Answer #638748 by fractalier(6550)\"\" \"About 
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Call the original fraction
\n" ); document.write( "\"x+%2F+%28x%2B3%29\"
\n" ); document.write( "Then we add one to top and bottom and get
\n" ); document.write( "\"%28x-1%29+%2F+%28x%2B2%29\"
\n" ); document.write( "This fraction is 1/14 less than the original...thus we have to solve
\n" ); document.write( "\"x+%2F+%28x%2B3%29+-+1%2F14+=+%28x-1%29+%2F+%28x%2B2%29\"
\n" ); document.write( "Now multiply everything by the lowest common denominator...
\n" ); document.write( "
\n" ); document.write( "and we get
\n" ); document.write( "14x(x+2) - (x+2)(x+3) = 14(x+3)(x-1)
\n" ); document.write( "14x^2 + 28x - x^2 - 5x - 6 = 14x^2 + 28x - 42
\n" ); document.write( "The 14x^2 and 28x cancel out...
\n" ); document.write( "-x^2 - 5x - 6 = -42
\n" ); document.write( "x^2 + 5x + 6 = 42
\n" ); document.write( "x^2 + 5x - 36 = 0
\n" ); document.write( "(x + 9)(x - 4) = 0
\n" ); document.write( "x = -9 and x = 4
\n" ); document.write( "The original fraction must be
\n" ); document.write( "4/7.
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