document.write( "Question 1023196: If 10th October 2014 is a Friday, then what was 3rd September 2013? \n" ); document.write( "

Algebra.Com's Answer #638744 by Edwin McCravy(20055) $\"\"$ $\"About$

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\n" ); document.write( "If 10th October 2014 is a Friday, then what was 3rd September 2013?
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document.write( "Let's figure it out.\r\n" );
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document.write( "10th October 2013 was a Thursday, because from a non-leap year to the\r\n" );
document.write( "next non-leap year, each date moves forward 1 week day, because\r\n" );
document.write( "365 days is exactly 1 more than a multiple of 7, and 364 = 52*7 \r\n" );
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document.write( "One week earlier, 3rd October 2013 was also Thursday. So  \r\n" );
document.write( "1st October was 2 days before Thursday, which would be a\r\n" );
document.write( "Tuesday.\r\n" );
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document.write( "That means the 30th September 2013 was Monday. Subtracting \r\n" );
document.write( "4 weeks or 28 days from the 30th gives that 2nd September 2013 \r\n" );
document.write( "was also on Monday, so 3rd September 2013 was a Tuesday.\r\n" );
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document.write( "Edwin

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