document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023135>Question 1023135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary.  The smaller angle is 15°less than one-half the measure of the larger angle. What are the measure of the angles?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638741 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger angle x.  The smaller must be 90-x, since they are complementary.  Then we can write<BR>\n" );
document.write( "90 - x = (1/2)x - 15<BR>\n" );
document.write( "Now add x and add 15 to both sides and get<BR>\n" );
document.write( "105 = (3/2)x<BR>\n" );
document.write( "Multiply by 2/3 and get<BR>\n" );
document.write( "x = 70 degrees...the other must be 20 degrees...<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );