document.write( "Question 1023166: Two investments totaling $53,000 produce an annual income of $3490. One investment yields 7% per year, while the other yields 6% per year. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #638727 by fractalier(6550)\"\" \"About 
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Call the amount invested at 7%, x.
\n" ); document.write( "Then the amount at 6% must be $53,000-x.
\n" ); document.write( "The set up looks like this:
\n" ); document.write( ".07x + .06(53000-x) = 3490
\n" ); document.write( ".07x + 3180 - .06x = 3490
\n" ); document.write( ".01x = 310
\n" ); document.write( "x = $31000 at 7%
\n" ); document.write( "and
\n" ); document.write( "53000-x = $22000 at 6%
\n" ); document.write( "
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