document.write( "Question 1023166: Two investments totaling $53,000 produce an annual income of $3490. One investment yields 7% per year, while the other yields 6% per year. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #638727 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call the amount invested at 7%, x. \n" ); document.write( "Then the amount at 6% must be $53,000-x. \n" ); document.write( "The set up looks like this: \n" ); document.write( ".07x + .06(53000-x) = 3490 \n" ); document.write( ".07x + 3180 - .06x = 3490 \n" ); document.write( ".01x = 310 \n" ); document.write( "x = $31000 at 7% \n" ); document.write( "and \n" ); document.write( "53000-x = $22000 at 6% \n" ); document.write( " |