document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023206>Question 1023206</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height of a box is 10 inches. The length is 3 inches more than the width. Find the width if the volume is 180 cubic inches. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638723 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well if the volume of the box is 180, and the height is ten, then the area of the base must be 180/10 = 18 square inches.<BR>\n" );
document.write( "Then we can write<BR>\n" );
document.write( "Area A = LW = 18 and L = W+3<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "(W+3)(W) = 18<BR>\n" );
document.write( "W^2 + 3W - 18 = 0<BR>\n" );
document.write( "(W + 6)(W - 3 = 0<BR>\n" );
document.write( "W = -6 or W = 3<BR>\n" );
document.write( "Thus the width is 3 inches.<BR>\n" );
document.write( "The box is 3\" x 6\" x 10\". </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );