document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017903>Question 1017903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> limit as x -> 3\r<BR>\n" );
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document.write( "(2sqrt(x+1)-4)/(2x^2-x-15) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638670 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can also use L'Hopital's rule:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=lim%28x-%3E3%2C%282sqrt%28x%2B1%29-4%29%2F%282x%5E2-x-15%29%29+=+lim%28x-%3E3%2C+%281%2Fsqrt%28x%2B1%29%29%2F%284x-1%29%29+=+lim%28x-%3E3%2C+1%2F%28%284x-1%29sqrt%28x%2B1%29%29%29+=+1%2F%28%284%2A3-1%29%28sqrt%283%2B1%29%29%29+=+1%2F22 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "(The limit has the indeterminate form 0/0.) </SPAN>\n" );
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