document.write( "Question 1023146: Suppose we draw a four card hand from a standard 52 card deck.
\n" ); document.write( "A) how many different hands contain 3 cards of the same value?\r
\n" ); document.write( "\n" ); document.write( "B) how many different hands contain 4 cards of the same value?
\n" ); document.write( "

Algebra.Com's Answer #638665 by mathmate(429)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Question:
\n" ); document.write( "Suppose we draw a four card hand from a standard 52 card deck.
\n" ); document.write( "A) how many different hands contain 3 cards of the same value?
\n" ); document.write( "B) how many different hands contain 4 cards of the same value?
\n" ); document.write( "
\n" ); document.write( "Solution:
\n" ); document.write( "Four-card hands means that order does not count.
\n" ); document.write( "There are 13 \"values\" in a deck, each in 4 different suits.
\n" ); document.write( "In the following, the combination \"n choose r\" is represented by
\n" ); document.write( "C(n,r)=n!/(r!(n-r)!)
\n" ); document.write( "
\n" ); document.write( "A) 3 cards of the same value
\n" ); document.write( "For each \"value\", i.e. Ace, 2, 3....10,J,Q,K, there are C(4,3)=4 ways to choose the three cards, AND (13-1)=12 different ways to choose the fourth card.
\n" ); document.write( "There are thus 4*12=48 different hands that contain 3 card of the same value for each value. Since there are 13 \"values\" per pack, so there are 13*48=624 such hands.
\n" ); document.write( "
\n" ); document.write( "B) 4 cards of the same value.
\n" ); document.write( "For each value, there is only C(4,4)=1 way to choose all four cards of the same value. Multiplied by 13 values, there are 13 such hands.
\n" ); document.write( "
\n" );