document.write( "Question 1023050: Find an equation of the line that satisfies the given conditions. Your answers should be in slope-intercept form. \r
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document.write( "(a) x-intercept -8; y-intercept of 6
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document.write( "(b) through (1,1) and perpendicular to the line 4x-8y=1
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document.write( "(c) through (4,5) and parallel to the y-axis \n" );
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Algebra.Com's Answer #638654 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "(a) x-intercept -8; y-intercept of 6 \n" ); document.write( "Gradient = 6/-8 = -3/4 \n" ); document.write( "Using line equation y - b = m(x - a) \n" ); document.write( "m = -3/4 and (a,b) = (-8, 0) \n" ); document.write( "y - 0 = -3/4(x -(-8)) \n" ); document.write( "y = -3/4(x + 8) \n" ); document.write( "y = -3/4x - 6 \n" ); document.write( "............... \n" ); document.write( "(b) through (1,1) and perpendicular to the line 4x-8y=1 \n" ); document.write( "Sort 4x - 8y = 1 into y = mx + c form \n" ); document.write( "-8y = -4x + 1 \n" ); document.write( "y = -4/-8 x + 1/-8 \n" ); document.write( "y = 1/2x - 1/8 \n" ); document.write( "Lines that are perpendicular to each other \n" ); document.write( "have gradients that multiply together to \n" ); document.write( "give -1 \n" ); document.write( "m1 x m2 = -1 \n" ); document.write( "1/2 x m2 = -1 \n" ); document.write( "m2 = -2 \n" ); document.write( "Using line equation y - b = m(x - a) \n" ); document.write( "m = -2 and (a,b) = (1,1) \n" ); document.write( "y - 1 = -2(x - 1) \n" ); document.write( "y - 1 = -2x + 2 \n" ); document.write( "y = -2x + 2 + 1 \n" ); document.write( "y = -2x + 3 \n" ); document.write( ".............. \n" ); document.write( "(c) through (4,5) and parallel to the y-axis \n" ); document.write( "A line parallel to the y axis would have 0 gradient. \n" ); document.write( "Equation would be x = 4 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " \n" ); document.write( " |