document.write( "Question 1023101: the average of first three numbers is double from fourth no. if the average of all four number is 28 find out the fourth number \n" ); document.write( "
Algebra.Com's Answer #638627 by god2012(113)![]() ![]() You can put this solution on YOUR website! Let the numbers be a,b,c and d. \n" ); document.write( "Average of first 3 numbers is double the 4th \n" ); document.write( "(a+b+c)/3 = 2d => (a+b+c) = 6d -----------eq.1\r \n" ); document.write( "\n" ); document.write( "Avg. of all 4 numbers is\r \n" ); document.write( "\n" ); document.write( "(a+b+c+d)/4 = 28 => /(a+b+c+d) = 28*4 = 112 ----eq.2 \n" ); document.write( "Put eq.1 in eq.2\r \n" ); document.write( "\n" ); document.write( "6d + d = 112 \n" ); document.write( "7d = 112 \n" ); document.write( "d = 112/7\r \n" ); document.write( "\n" ); document.write( "d = 16 \n" ); document.write( "So, the 4th number is 16 \n" ); document.write( " |