document.write( "Question 1023073: A country's population in 1992 was 72 million. In 1998 it was 76 million. Estimate the population in 2012 using the exponential growth formula. Round your answer to the nearest million.
\n" ); document.write( "P=Ae^kt
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Algebra.Com's Answer #638590 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
You want to show it in pure text as P=Ae^(kt) and when rendered, \"P=Ae%5E%28kt%29\".\r
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\n" ); document.write( "\n" ); document.write( "Let t be number of years after 1992. This means that 1998 uses t=6. Also, year 2012 is t=10. A=72 for 72 million people at t=0.\r
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\n" ); document.write( "\n" ); document.write( "\"76=72%2Ae%5E%28k%2A6%29\"
\n" ); document.write( "\"ln%2876%29=ln%2872%2Ae%5E%28k%2A6%29%29\"
\n" ); document.write( "\"ln%2876%29=ln%2872%29%2B6k%2Aln%28e%29\"
\n" ); document.write( "\"6k%2A1%2Bln%2872%29=ln%2876%29\"
\n" ); document.write( "\"6k=ln%2876%29-ln%2872%29\"
\n" ); document.write( "\"k=%28ln%2876%29-ln%2872%29%29%2F6\"--------compute this for the value of k.\r
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\n" ); document.write( "\n" ); document.write( "Now your model is \"P=72%2Ae%5E%280.009011%2At%29\"; just let t=10 and evaluate P.
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