document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023025>Question 1023025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello my name is Juan I'm in college, but I have a big problem I have 3 questions  \r<BR>\n" );
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document.write( "The question says Solve algebraically show all work put your answer on the line. For calculation and final answer, round to the nearest hundredths. Make sure your handwriting is legible to me. check your answers\r<BR>\n" );
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document.write( "solve write your solutions as ordered pairs \r<BR>\n" );
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document.write( "1) x^2+8x-12=0\r<BR>\n" );
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document.write( "I solved like this (x-6) (x-2) or (x+6)(x-2)<BR>\n" );
document.write( " I have try to also solved like this \r<BR>\n" );
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document.write( "x^2+8x-12=0\r<BR>\n" );
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document.write( "x^2+8x=12\r<BR>\n" );
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document.write( "x(x+8)=12\r<BR>\n" );
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document.write( "x(x+8)-12=0/x\r<BR>\n" );
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document.write( "x+8-12=0 \r<BR>\n" );
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document.write( "x-4=0\r<BR>\n" );
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document.write( "x=4 Now I don't know if this answer is correct please help me I have tried everything but I still cannot found the answer\r<BR>\n" );
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document.write( "the next question is \r<BR>\n" );
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document.write( "5x^2+19x=35\r<BR>\n" );
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document.write( "what I have tried is almost the same as the last one\r<BR>\n" );
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document.write( "5x^2+19x=35\r<BR>\n" );
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document.write( "5x(x+19)=35\r<BR>\n" );
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document.write( "x+19=35/5\r<BR>\n" );
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document.write( "x+19=7\r<BR>\n" );
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document.write( "x+19-7=0\r<BR>\n" );
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document.write( "x+12=0\r<BR>\n" );
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document.write( "x=-12\r<BR>\n" );
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document.write( "and the third question is \r<BR>\n" );
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document.write( "-6x^2-x+5=0\r<BR>\n" );
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document.write( "(-1)-6x^2-x+5=0\r<BR>\n" );
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document.write( "6x-x+5=0\r<BR>\n" );
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document.write( "(6x-1)(x+5) Please help me I have seriously tried everything \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638575 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> On 1), when you FOIL you have to end up with x^2+8x-12=0. But this number is irreducible. The most you can do is x(x+8) = 12 or x(x+8)-12 = 0 etc. which is how you have it on your second answer. However, since it's irreducible I don't see a way to write it as an ordered pair. Maybe I'm missing something.<BR>\n" );
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document.write( "5x^2+19x-35 = 0<BR>\n" );
document.write( "x^2+(19x)/5-7 = 0<BR>\n" );
document.write( "x^2+(19 x)/5 = 7<BR>\n" );
document.write( "x^2+(19 x)/5+361/100 = 1061/100<BR>\n" );
document.write( "(x+19/10)^2 = 1061/100<BR>\n" );
document.write( "x+19/10 = sqrt(1061)/10 or x+19/10 = -sqrt(1061)/10<BR>\n" );
document.write( "Subtract 19/10 from both sides:<BR>\n" );
document.write( "x = sqrt(1061)/10-19/10 or x+19/10 = -sqrt(1061)/10<BR>\n" );
document.write( "x = sqrt(1061)/10-19/10 or x = -19/10-sqrt(1061)/10<BR>\n" );
document.write( "Note: When you went from 5x(x+19)=35 to x+19=35/5 you ignored an x and the fact that 19x also has to be divided by 5, in other words, you would have:x(x+19)/5= 7 which is what I have (I have x^2(19x)/5 = 7).<BR>\n" );
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document.write( "-6x^2-x+5= 0 Finally, something to work with!!<BR>\n" );
document.write( "-(x+1) (6 x-5) = 0<BR>\n" );
document.write( "Suerte en tus estudios.<BR>\n" );
document.write( "J </SPAN>\n" );
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