document.write( "Question 1022868: Log(x+1)=2logx \n" ); document.write( "
Algebra.Com's Answer #638564 by ankor@dixie-net.com(22740)\"\" \"About 
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Log(x+1) = 2logx
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\n" ); document.write( " \"log%28%28x%2B1%29%29=log%28%28x%5E2%29%29\"
\n" ); document.write( "therefore
\n" ); document.write( "x + 1 = x^2
\n" ); document.write( "A quadratic equation
\n" ); document.write( "0 = x^2 - x - 1
\n" ); document.write( "use the quadratic formula a=1; b=-1; c-1
\n" ); document.write( "Two solutions
\n" ); document.write( "x = -.618
\n" ); document.write( "x = 1.618, only solution in the original equation
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