document.write( "Question 1022954: A does 7/10 of a piece of work in 14 days. He then calls B, and they finish the work in 2 days. How long would B take to do the work by himself? \n" ); document.write( "
Algebra.Com's Answer #638536 by fractalier(6550)\"\" \"About 
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The normal set up for work problems is
\n" ); document.write( "\"t%2FA+%2B+t%2FB+=+1\"
\n" ); document.write( "In our problem, A completes 7/10 of the job in 14 days. That means he could do it all in 20 days.
\n" ); document.write( "Our t in the set up is 2 days, and the 1 job in the set up is only 3/10 job here.
\n" ); document.write( "So our equation looks like this
\n" ); document.write( "\"2%2F20+%2B+2%2FB+=+3%2F10\"
\n" ); document.write( "and when you work that out you find
\n" ); document.write( "B = 10 days
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