document.write( "Question 1022923: Please help me solve this equation:
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document.write( "Jun-Pei is twice as old as her friend, Pristine. Pristine is 5 years older than Ashley. In 5 years, Jun-Pei will be three times as old as Ashley. How old is Pristine now? \n" );
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Algebra.Com's Answer #638514 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! Set J = age of Jun-Pei \n" ); document.write( "Set P = age of Pristine \n" ); document.write( "Set A = age of Ashley \n" ); document.write( "J = 2P \n" ); document.write( "P = A + 5 \n" ); document.write( "J + 5 = 3A \n" ); document.write( "Since J = 2P \n" ); document.write( "divide each side by 2 \n" ); document.write( "J/2 = P \n" ); document.write( "Since P = A + 5 \n" ); document.write( "J/2 = A + 5 \n" ); document.write( "multiply each side by 2 \n" ); document.write( "J = 2A + 10 \n" ); document.write( "Substitute 2A + 10 for J in J + 5 = 3A \n" ); document.write( "( 2A + 10 ) + 5 = 3A \n" ); document.write( "2A + 15 = 3A \n" ); document.write( "add -2A to each side \n" ); document.write( "15 = A \n" ); document.write( "Since J = 2A + 10 \n" ); document.write( "J = 2*15 + 10 \n" ); document.write( "J = 40 \n" ); document.write( "Since P = J/2 \n" ); document.write( "P = 40/2 \n" ); document.write( "P = 20 \n" ); document.write( "So A = 15 , P = 20 and J = 40 \n" ); document.write( " |