document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12591>Question 12591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with this problem: 3 log 3 x=5    (the second \"3\" is under the word \"log\").  I can't seem to follow the pattern on my textbook.  I would love to see the steps to working out this problem. thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6385 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3+%2Alog%283%2Cx%29+=+5+ ALIGN=MIDDLE  ALT=\"3+%2Alog%283%2Cx%29+=+5+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "There are probably several ways to go about this.  I'd say to divide both sides by 3, and get <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%283%2Cx%29+=+5%2F3 ALIGN=MIDDLE  ALT=\"log%283%2Cx%29+=+5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Next use the basic definition of logarithms to convert to exponential form.  Remember the definition says <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log%28b%2Cx%29+=+y ALIGN=MIDDLE  ALT=\"+log%28b%2Cx%29+=+y\"   DISABLED_style= \"max-width:90%; height:auto;\" > means <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5Ey+=+x ALIGN=MIDDLE  ALT=\"b%5Ey+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" >?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "In the same way, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%283%2Cx%29+=+5%2F3 ALIGN=MIDDLE  ALT=\"log%283%2Cx%29+=+5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E%285%2F3%29+=+x ALIGN=MIDDLE  ALT=\"3%5E%285%2F3%29+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "What you are trying to find is x, and that's it!! x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E%285%2F3%29+ ALIGN=MIDDLE  ALT=\"3%5E%285%2F3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Is that enough, or you could probably rewrite this as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A+%283%5E%282%2F3%29+%29+ ALIGN=MIDDLE  ALT=\"3%2A+%283%5E%282%2F3%29+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which means <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A+%28+root%283%2C9%29+%29 ALIGN=MIDDLE  ALT=\"3%2A+%28+root%283%2C9%29+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, but that's getting carried away if you ask me.  Easier to calculate it and say approximately 6.24.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "R^2 at SCC </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );