document.write( "Question 1022928: The length of a new rectangular playing field is 66 yards longer than triple the width. If the perimeter of the rectangular playing field is 476 ​yards, what are its​ dimensions? \n" ); document.write( "
Algebra.Com's Answer #638492 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Make the width = 'x'
\n" ); document.write( "Length = 66 + 3x
\n" ); document.write( "Perimeter = 2 x Width + 2 x Length
\n" ); document.write( "476 = 2(x) + 2(66 + 3x)
\n" ); document.write( "476 = 2x + 132 + 6x
\n" ); document.write( "Collect like terms.
\n" ); document.write( "2x + 6x = 476 - 132
\n" ); document.write( "8x = 344
\n" ); document.write( "x = 43
\n" ); document.write( "Width = 43 yards
\n" ); document.write( "Length = 195 yards
\n" ); document.write( "Hope this helps :-)
\n" ); document.write( "
\n" );