document.write( "Question 1022928: The length of a new rectangular playing field is 66 yards longer than triple the width. If the perimeter of the rectangular playing field is 476 yards, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #638492 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the width = 'x' \n" ); document.write( "Length = 66 + 3x \n" ); document.write( "Perimeter = 2 x Width + 2 x Length \n" ); document.write( "476 = 2(x) + 2(66 + 3x) \n" ); document.write( "476 = 2x + 132 + 6x \n" ); document.write( "Collect like terms. \n" ); document.write( "2x + 6x = 476 - 132 \n" ); document.write( "8x = 344 \n" ); document.write( "x = 43 \n" ); document.write( "Width = 43 yards \n" ); document.write( "Length = 195 yards \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |