document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022899>Question 1022899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE MEAN NUMBER OF DEFECTIVE PRODUCTS PRODUCED IN A FACTORY IN ONE DAY IS 21.WHAT IS THE PROBABILITY THAT IN A SPAN OF 3 DAYS THERE WILL BE MORE THAN 58 BUT LESS THAN 64 DEFECTIVE PRODUCTS </SPAN>\n" );
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document.write( "Question:<BR>\n" );
document.write( "THE MEAN NUMBER OF DEFECTIVE PRODUCTS PRODUCED IN A FACTORY IN ONE DAY IS 21.WHAT IS THE PROBABILITY THAT IN A SPAN OF 3 DAYS THERE WILL BE MORE THAN 58 BUT LESS THAN 64 DEFECTIVE PRODUCTS<BR>\n" );
document.write( " <BR>\n" );
document.write( "Solution:<BR>\n" );
document.write( "Assuming the number of defective products of each day is independent of previous days, the Poisson distribution may be used to model this situation.<BR>\n" );
document.write( "Average number of defects in 3 days = 3*21=63=&lambda;.<BR>\n" );
document.write( "P(k;&lambda;)=&lambda;^k*e^(-&lambda;)/k!<BR>\n" );
document.write( "We need to calculate <BR>\n" );
document.write( "P(58<k<64;&lambda;)=P({59,60,61,62,63};&lambda;)<BR>\n" );
document.write( "=0.04555+0.04783+0.04940+0.05020+0.05020<BR>\n" );
document.write( "=0.2432\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );