document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022863>Question 1022863</A>: <I><SPAN STYLE=\"word-break: break-all;\">     Suppose that you invest $20,000 into two accounts paying 7% and 9% annual interest, respectively.  If the total interest earned for the year is $1550, how much was invested at each rate? For this question, I only want you to tell me how you would set the equation(s) up to solve this.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638443 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK, I'll take you up to the equations. If you get stuck email me.<BR>\n" );
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document.write( "20,000 at 0.07 and 0.09 earn 1,550.<BR>\n" );
document.write( "Let's call the amount invested at 0.07 x. <BR>\n" );
document.write( "The rest of the money is invested at 0.09... how much is this amount? Well, out of 20,000, if x is invested at 0.07, that leaves 20,000-x to invest at 0.09:<BR>\n" );
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document.write( "0.07x+0.09(20,000-x) = 1,550<BR>\n" );
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document.write( "You take it from there.<BR>\n" );
document.write( "J </SPAN>\n" );
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