document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022815>Question 1022815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of a regular 24-gon with perimeter 72.<BR>\n" );
document.write( "Round your answer to the nearest thousandth.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638414 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of a regular 24-gon with perimeter 72.<BR>\n" );
document.write( "Round your answer to the nearest thousandth. <BR>\n" );
document.write( "----<BR>\n" );
document.write( "Break it into 24 equilateral triangles.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Find the area of one of those equi triangles.<BR>\n" );
document.write( "----<BR>\n" );
document.write( "each side is 72/24 = 3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Sketch the altitude of the triangle.<BR>\n" );
document.write( "You then have 2 right triangles.<BR>\n" );
document.write( "base = 1.5<BR>\n" );
document.write( "hypotenuse = 3<BR>\n" );
document.write( "altitude = sqrt(3^2 - 1.5^2] = 2.6<BR>\n" );
document.write( "----<BR>\n" );
document.write( "area = (1/2)base*alt = (0.5)*3*2.6 = 3.897<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Total Area = 24*3.897 = 93.521 sq.units<BR>\n" );
document.write( "==========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );