document.write( "Question 1022728: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM PLEASE PLEASE PLEASE ANSWER WITH STEP BY STEP WILL BE APPRECIATED!!! THANKS IN ADVANCE ☺
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document.write( "The niagara falls sky wheel one of the tallest ferris wheels in north america is in niagara falls ontario ot has a diameter of 50.5 m and rotates 1 revolutionin 2 min the lowest point on the wheel is 2.5m from the ground
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document.write( "a) sketch a graph that shows the height of a rider over time for one rotation
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document.write( "b) what is the highest point a rider will reach?
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document.write( "c)Write an equation that will model the height of a rider over time .
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document.write( "d)use your equation to find the height of the rider after 10 seconds
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document.write( "e)How would your graph and equation change if the skywheel was set to a max speed of 1.5 revolution per min? \n" );
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Algebra.Com's Answer #638352 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! at time 0, the height is 2.5m \n" ); document.write( ": \n" ); document.write( "With a diameter of 50.5 meters, the wheel has a radius of 25.25 meters. The height will oscillate with amplitude of 25.25 meters above and below the center. \n" ); document.write( ": \n" ); document.write( "Riders board 2.5 meters above ground level, so the center of the wheel must be located 25.25 + 2.5 = 27.75 meters above ground level. The midline of the oscillation will be at 27.75 meters. \n" ); document.write( ": \n" ); document.write( "The wheel takes 2 minutes to complete 1 revolution, so the height will oscillate with period of 2 minutes. \n" ); document.write( ": \n" ); document.write( "Lastly, since the rider boards at the lowest point, the height will start at the smallest value and increase, following the shape of a flipped cosine curve. \n" ); document.write( ": \n" ); document.write( "The equation for the rider's height will be \n" ); document.write( ": \n" ); document.write( "h(t) = -25.25cos(pi*t) + 27.75 \n" ); document.write( ": \n" ); document.write( " |