document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022732>Question 1022732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a bag contains 160 coins, there are coins of 10 and 25 cents. find the number of coin of 25 cents, if there is $26.80 in total </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638343 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of dimes and quarters, x and y.  Then we can write<BR>\n" );
document.write( "x + y = 160  and the value equation is<BR>\n" );
document.write( "10x + 25y = 2680   (we work in cents)<BR>\n" );
document.write( "Now multiply the top equation by ten and subtract it from the bottom...we get<BR>\n" );
document.write( "10x + 25y = 2680<BR>\n" );
document.write( "-(10x + 10y = 1600)<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "15y = 1080<BR>\n" );
document.write( "and dividing by 15...<BR>\n" );
document.write( "y = 72 quarters...that means there are<BR>\n" );
document.write( "x = 160 - 72 = 88 dimes </SPAN>\n" );
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