document.write( "Question 1022712: what is e^x - 5e^-x - 4 = 0\r
\n" ); document.write( "\n" ); document.write( "how to get the appropriate answer hehehe thanks!
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Algebra.Com's Answer #638326 by Theo(13342)\"\" \"About 
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start with e^x - 5e^-x - 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "since e^-x is the same as 1/e^x, this becomes e^x - 5/e^x - 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of that equation by e^x to get (e^x)^2 - 5 - 4e^x = 0\r
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\n" ); document.write( "\n" ); document.write( "reorder the terms in descending order of degree to get (e^x)^2 - 4e^x - 5 = 0\r
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\n" ); document.write( "\n" ); document.write( "this is a quadratic equation where the argument of the function is e^x.\r
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\n" ); document.write( "\n" ); document.write( "let some other variable name be equal to e^x.\r
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\n" ); document.write( "\n" ); document.write( "i'll use the variable name of b.\r
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\n" ); document.write( "\n" ); document.write( "the equation becomes b^2 - 4b - 5 = 0.\r
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\n" ); document.write( "\n" ); document.write( "now it's easier to see that it is a quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "factor this quadratic to get (b-5) * (b+1) = 0\r
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\n" ); document.write( "\n" ); document.write( "solve for b to get b = 5 or b = -1.\r
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\n" ); document.write( "\n" ); document.write( "since b is equal to e^x, this becomes e^x = 5 or e^x = -1\r
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\n" ); document.write( "\n" ); document.write( "solve for x in each of these equations by taking the natural log of both sides of each equation.\r
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\n" ); document.write( "\n" ); document.write( "you will get ln(e^x) = ln(5) or ln(e^x) = ln(-1).\r
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\n" ); document.write( "\n" ); document.write( "since you cannot take the log of a negative number and get a real answer, then the only viable solution is ln(e^x) = ln(5).\r
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\n" ); document.write( "\n" ); document.write( "since ln(e^x) is the same as x * ln(e) and since ln(e) is equal to 1, then you get ln(e^x) is equal to x * 1 which is equal to x.\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes x = ln(5).\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "you can go one step further by finding the natural log of 5 to get x = 1.609437912.\r
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\n" ); document.write( "\n" ); document.write( "x = ln(5) is the exact solution.
\n" ); document.write( "x = 1.609437912 is an approximate solution since it does not appear that ln(5) results in a rational number.\r
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