document.write( "Question 1022638: How do i find the inverse of f(x) = 1/2 (x-2)³ +3 \r
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Algebra.Com's Answer #638314 by robertb(5830)\"\" \"About 
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I will assume the function is \"+f%28x%29+=+%281%2F2%29%28x-2%29%5E3+%2B3+\"\r
\n" ); document.write( "\n" ); document.write( "This function is one-to-one in its domain, hence its inverse function will exist.\r
\n" ); document.write( "\n" ); document.write( "Now let \"+y+=+%281%2F2%29%28x-2%29%5E3+%2B3+\"\r
\n" ); document.write( "\n" ); document.write( "==> \"+y-3=+%281%2F2%29%28x-2%29%5E3+\"\r
\n" ); document.write( "\n" ); document.write( "==> \"2y-6+=+%28x-2%29%5E3+\"\r
\n" ); document.write( "\n" ); document.write( "==> \"root%283%2C+2y-6%29+=+x-2\" after taking cube roots of both sides.\r
\n" ); document.write( "\n" ); document.write( "==> \"root%283%2C+2y-6%29+%2B+2+=+x\"\r
\n" ); document.write( "\n" ); document.write( "Now interchange the positions of x and y:\r
\n" ); document.write( "\n" ); document.write( " \"root%283%2C+2x-6%29+%2B+2+=+y\"\r
\n" ); document.write( "\n" ); document.write( "This is the inverse function of \"+f%28x%29+=+%281%2F2%29%28x-2%29%5E3+%2B3+\"
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