document.write( "Question 1022600: resolver\r
\n" ); document.write( "\n" ); document.write( "raiz cuadrada ; raiz cubica
\n" ); document.write( " sqrt (2x+1=5) ; sqrt3 (4x-4=2)
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Algebra.Com's Answer #638278 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
In pure text in preparation for the site's rendering tags:
\n" ); document.write( "sqrt(2x+1)=5 y root(3,(4x-4))=2\r
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\n" ); document.write( "\n" ); document.write( "...entonces los 'rendering tags' puestos:
\n" ); document.write( "\"sqrt%282x%2B1%29=5\" y \"root%283%2C%284x-4%29%29=2\".\r
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\n" ); document.write( "\n" ); document.write( "Solo trabajo aqui con el raiz cubica.
\n" ); document.write( "Levante los dos miembros al poder 3.\r
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\n" ); document.write( "\n" ); document.write( "\"%28root%283%2C%284x-4%29%29%29%5E3=2%5E3\"\r
\n" ); document.write( "\n" ); document.write( "\"root%283%2C%284x-4%29%29root%283%2C%284x-4%29%29root%283%2C%284x-4%29%29=8\"\r
\n" ); document.write( "\n" ); document.write( "\"4x-4=8\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=8%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=12\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=3%29\"\r
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "El para raiz cuadrada se resuelve en manera semejante como el para raiz cubica. Ahora, levante los dos miembros al poder 2, y entonces simplifica; ...
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