document.write( "Question 1021025: 2n!
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Algebra.Com's Answer #638266 by Edwin McCravy(20055) $\"\"$ $\"About$

You can put this solution on YOUR website!
2n! divided by (n-3)! = 84n
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document.write( "The left side is a factorial.\r\n" );
document.write( "For the right side to be a factorial beginning\r\n" );
document.write( "with 7*6, it must be 7! or 7*6*5*4*3*2*1.\r\n" );
document.write( "Then (n-3)! must be 5*4*3*2*1 or 5!\r\n" );
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document.write( "Checking:\r\n" );
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document.write( "So it checks:\r\n" );
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document.write( "Solution: \r\n" );
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document.write( "Edwin

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