document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022581>Question 1022581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many ounces of 6% should be combined with a 20% in order to create a 70-ounce mixture that is 12% alcohol? <BR>\n" );
document.write( "Amount of 6%= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638255 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 6% solution x.<BR>\n" );
document.write( "Then the amount of 20% solution would be 70-x.<BR>\n" );
document.write( "We then set it up like this:<BR>\n" );
document.write( ".06x + .20(70-x) = .12(70)<BR>\n" );
document.write( ".06x + 14 - .20x = 8.4<BR>\n" );
document.write( "-.14x = -5.6<BR>\n" );
document.write( "x = 40 ounces at 6% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );