document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022572>Question 1022572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Make (f) the subject of the formula and simplify.\r<BR>\n" );
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document.write( "A=3(F-f)/L </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638238 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = (3(F-f))/L<BR>\n" );
document.write( "Let's solve for f:<BR>\n" );
document.write( "A = (3(F-f))/L is equivalent to (3(F-f))/L = A, so I'm going to write it this way:<BR>\n" );
document.write( "(3(F-f))/L = A<BR>\n" );
document.write( "Multiply both sides by L/3:<BR>\n" );
document.write( "F-f = (AL)/3<BR>\n" );
document.write( "Subtract F from both sides:<BR>\n" );
document.write( "-f = (A L)/3-F<BR>\n" );
document.write( "Finally, multiply both sides by -1:<BR>\n" );
document.write( "f = F-(AL)/3 </SPAN>\n" );
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