document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022569>Question 1022569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Travis made a business trip of 198 miles.  He averaged 63 mph for the first part of the trip and 54 mph for the second part.  If the trip took 3.5 hours, how long did he travel at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638229 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the time he took on the first part, t.<BR>\n" );
document.write( "Then the time he took on the second part was 3.5-t.<BR>\n" );
document.write( "Then we can write, noting that rate times time = distance,<BR>\n" );
document.write( "63t + 54(3.5 - t) = 198<BR>\n" );
document.write( "63t + 189 - 54t = 198<BR>\n" );
document.write( "9t + 189 = 198<BR>\n" );
document.write( "9t = 9<BR>\n" );
document.write( "t = 1 hour at 63 mph<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "3.5-t = 2.5 hours at 54 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );