document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022546>Question 1022546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Double the larger number plus three times the smaller number makes 19 the difference between the numbers is 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638228 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger and smaller numbers x and y.  Then we have<BR>\n" );
document.write( "x - y = 2  and<BR>\n" );
document.write( "2x + 3y = 19<BR>\n" );
document.write( "Solve the first and substitute into the second...<BR>\n" );
document.write( "x = y+2<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "2(y+2) + 3y = 19<BR>\n" );
document.write( "2y + 4 + 3y = 19<BR>\n" );
document.write( "5y + 4 = 19<BR>\n" );
document.write( "5y = 15<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "x = 5. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );