document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87845>Question 87845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a ladder is 14 feet away from the wall.  The top of the ladder is 17 feet from the floor.  Find the length of the ladder to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63819 by </B><A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><B>jayanthihemkos@yahoo.com(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The base of a ladder is 14 feet away from the wall.  The top of the ladder is 17 feet from the floor.  Find the length of the ladder to the nearest thousandth.\r<BR>\n" );
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document.write( "AB = 17 ft  , BC = 14 FT\r<BR>\n" );
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document.write( "applying pythagros theorem we have\r<BR>\n" );
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document.write( "AC^2 =  AB^2+BC^2\r<BR>\n" );
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document.write( "AC = SQUARE ROOT OF AB^2+BC^2\r<BR>\n" );
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document.write( "AC =SQUARE ROOT OF 17^2 + 14^2\r<BR>\n" );
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document.write( "AC =SQUARE ROOT OF 289 + 196\r<BR>\n" );
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document.write( "AC =SQUARE ROOT OF 485\r<BR>\n" );
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document.write( "AC = 22.022\r<BR>\n" );
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document.write( "HENCE THE LENGTH OF THE LADDER = 22.022 ft<BR>\n" );
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