document.write( "Question 1022499: Problem Page\r
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document.write( "The length of a rectangle is
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document.write( "6
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document.write( "cm
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document.write( " longer than its width.
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document.write( "If the perimeter of the rectangle is
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document.write( "44
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document.write( "cm
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document.write( ", find its area. \n" );
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Algebra.Com's Answer #638158 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the width = 'x' \n" ); document.write( "Length = 6 + x \n" ); document.write( "Perimeter = 2 x Width + 2 x Length \n" ); document.write( "44 = 2(x) + 2(6 + x) \n" ); document.write( "44 = 2x + 12 + 2x \n" ); document.write( "Collect like terms: \n" ); document.write( "4x = 32 \n" ); document.write( "x = 8 \n" ); document.write( "Width = 8 cm \n" ); document.write( "Length = 14 cm \n" ); document.write( "Area = Length x Width \n" ); document.write( "Area = 14 x 8 \n" ); document.write( "Area = 112 cm^2 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |