document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87673>Question 87673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The right circular cone has a volume = 24(pi=3.14)cubic cm and r = 3, What is the height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63812 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">        <BR>\n" );
document.write( "         volume = v = 24 cc<BR>\n" );
document.write( "          radius= r = 3.cms<BR>\n" );
document.write( "          height = h = ?<BR>\n" );
document.write( "               v = pi.r^2.h/3 = (3.14).3.3.h/3 = (3.14).3.h<BR>\n" );
document.write( "               24 = (3.14).3.h  therefore h = 24/9.42 = 2.54cms<BR>\n" );
document.write( "                                  therefore h = 2.54cms </SPAN>\n" );
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