document.write( "Question 87932: use the quadratic function (((f(x)=-2/5(x+2)^2-3))) to answer the following:\r
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document.write( "A)Find the vertex\r
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document.write( "B)What is the axis of symmetry?\r
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document.write( "C)How does the graph open(up or down)?\r
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document.write( "Thanks you for any help you can provide. what i have so far is the formula which i believe is correct: (-b/2a,f(-b/2a)). I also have a=-2/5 b=(x+2)^2 but I'm not positive just because its a fraction, I'm unsure. well thanks for your help! \n" );
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Algebra.Com's Answer #63811 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "This is in quadratic form: \n" ); document.write( "* \"a\" determines if the parabola opens up or down \n" ); document.write( "~> positive \"a\" means up \n" ); document.write( "~> negative \"a\" means down \n" ); document.write( "* \"h\" and \"k\" determines the vertex \n" ); document.write( "Vertex (h,k) \n" ); document.write( " \n" ); document.write( "a = -2/5 \n" ); document.write( "h = -2 \n" ); document.write( "k = -3 \n" ); document.write( "Vertex: (-2,-3) \n" ); document.write( "Opens downward \n" ); document.write( "The axis of symmetry is \n" ); document.write( " |