document.write( "Question 1022428: the larger of two numbers is 4 less than fives times the smaller. when the smallest number is subtracted from the larger, the difference is 4. find the two numbers \n" ); document.write( "
Algebra.Com's Answer #638105 by addingup(3677)\"\" \"About 
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x-4 = 5y (1)
\n" ); document.write( "x-y = 4 (2)
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\n" ); document.write( "In equation (1) subtract 5y and add 4 on both sides:
\n" ); document.write( "x-5y = 4 Now we have a new equation, let's call it (3)
\n" ); document.write( "In equation (2) multiply all times -5:
\n" ); document.write( "-5x+5y = -20 Add this equation to (3)
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\n" ); document.write( "x-5y = 4
\n" ); document.write( "+
\n" ); document.write( "-5x+5y = -20
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\n" ); document.write( "-4x = -16 divide both sides by -4 and remember -/- = +
\n" ); document.write( "x = 4 Now let's find y:
\n" ); document.write( "x-y = 4
\n" ); document.write( "4-y = 4
\n" ); document.write( "4 = 4+y
\n" ); document.write( "0 = y
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\n" ); document.write( "The problem has two equations:
\n" ); document.write( "x-4 = 5y (1)
\n" ); document.write( "x-y = 4 (2)
\n" ); document.write( "Let's try our numbers:
\n" ); document.write( "4-4 = 5(0); 0 = 0 this one is correct. Next:
\n" ); document.write( "4-0 = 4 This is also correct. We have the correct answers
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