document.write( "Question 1022424: disciss continuity and differentibility at x=1
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document.write( "f(x)={ x if 0<=x<=1 }
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document.write( " 2x_1 if 1<=x<=2 \n" );
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Algebra.Com's Answer #638098 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What does \"2x_1\" mean?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |