document.write( "Question 1022333: Suppose tan(alpha) = \"5%2F6\" and alpha terminates in Quadrant III.
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Algebra.Com's Answer #638069 by ikleyn(52788)\"\" \"About 
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document.write( "Suppose tan(alpha) =  \"5%2F6\" and alpha terminates in Quadrant III.\r\n" );
document.write( "Without simplifying any square roots, calculate \r\n" );
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document.write( "sin(alpha) =  \"-tan%28alpha%29%2Asqrt%281%2F%281+%2B+tan%5E2%28alpha%29%29%29\" = \"-%285%2F6%29%2Asqrt%281%2F%281+%2B+%285%2F6%29%5E2%29%29\" = \"-%285%2F6%29%2Asqrt%2836%2F%2825%2B36%29%29\" = \"-5%2Fsqrt%2861%29%29\".\r\n" );
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document.write( "              The sign \"-\" (minus) was chosen because the angle \"alpha\" terminates in Quadrant III.\r\n" );
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document.write( "               \r\n" );
document.write( "cos(alpha) =  \"-sqrt%281%2F%281+%2B+tan%5E2%28alpha%29%29%29\" = \"-sqrt%281%2F%281+%2B+%285%2F6%29%5E2%29%29\" = \"-sqrt%2836%2F%2825%2B36%29%29\" = \"-6%2Fsqrt%2861%29%29\".\r\n" );
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document.write( "              The sign \"-\" (minus) was chosen because the angle \"alpha\" terminates in Quadrant III.\r\n" );
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document.write( "cot(alpha) =  \"1%2Ftan%28alpha%29\" = \"6%2F5\".\r\n" );
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document.write( "sec(alpha) =  \"1%2Fcos%28alpha%29\" = \"-sqrt%2861%29%2F6\".\r\n" );
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document.write( "csc(alpha) =  \"1%2Fsin%28alpha%29\" = \"-sqrt%2861%29%2F5\".\r\n" );
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